Find the LCD for the fractions $\displaystyle\frac{5}{12}$ and $\displaystyle\frac{7}{18}$.

Find the LCD for $\displaystyle\frac{3}{4}$ and $\displaystyle\frac{1}{6}$.

Add: $\displaystyle\frac{5}{12}+\displaystyle\frac{7}{18}$

Add: $\displaystyle\frac{3}{4}+\displaystyle\frac{1}{6}$

Subtract: $\displaystyle\frac{7}{15}-\displaystyle\frac{3}{10}$

Subtract: $\displaystyle\frac{3}{5}-\displaystyle\frac{1}{6}$

Add: $\displaystyle\frac{1}{6}+\displaystyle\frac{1}{8}+\displaystyle\frac{1}{4}$

Subtract: $3-\displaystyle\frac{5}{6}$

Add: $3\displaystyle\frac{2}{3}+4\displaystyle\frac{1}{5}$

Add: $5\displaystyle\frac{3}{4}+9\displaystyle\frac{5}{6}$

Add: $5\dfrac{2}{3}+6\dfrac{8}{9}$

Add: $3\dfrac{1}{4}+2\dfrac{3}{5}+1\dfrac{9}{10}$

Subtract: $3\dfrac{9}{10}-1\dfrac{3}{10}$

Subtract: $12\displaystyle\frac{7}{10}-8\displaystyle\frac{3}{5}$

Subtract: $10-5\displaystyle\frac{2}{7}$

Subtract: $8\dfrac{1}{4}-3\dfrac{3}{4}$

Subtract: $4\dfrac{3}{4}-1\dfrac{5}{6}$

Simplify: $\left(\displaystyle\frac{3}{4}\right)^2$

Simplify: $\left(\displaystyle\frac{5}{6}\right)^2 \cdot \displaystyle\frac{1}{2}$

What is the quotient of $\displaystyle\frac{8}{3}$ and $\displaystyle\frac{1}{6}$, increased by $5$.

Simplify $32\div \left(\displaystyle\frac{4}{3}\right)^2 +75\div \left(\displaystyle\frac{5}{2}\right)^2$

Simplify: $5+\left(2\displaystyle\frac{1}{2}\right)\cdot\left(3\displaystyle\frac{2}{3}\right)$

Simplifty: $$\left(\frac{3}{4}+\frac{5}{8}\right)\left(2\frac{3}{8}+1\frac{1}{4}\right)$$

Simplify: $\displaystyle\frac{3}{5}+\displaystyle\frac{1}{2}\left(3\displaystyle\frac{2}{3}+4\displaystyle\frac{1}{3}\right)^2$

Simplify: $\displaystyle\frac{\displaystyle\frac{3}{4}}{\displaystyle\frac{5}{6}}$

Simplify: $\displaystyle\frac{\displaystyle\frac{1}{2}+\displaystyle\frac{2}{3}}{\displaystyle\frac{3}{4}-\displaystyle\frac{1}{6}}$

Simplify: $\displaystyle\frac{3+\displaystyle\frac{1}{2}}{2-\displaystyle\frac{3}{4}}$

Simplify: $\displaystyle\frac{10\displaystyle\frac{1}{3}}{8\displaystyle\frac{2}{3}}$